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2024届北京专家卷·英语(四)4答案部分示例

书面表达One possible version;Currently, I notice that students in our school are commonly sleepy in class,with low learning efficiency. The fact is that they get up too early and have longhours at school. As a student, I strongly recommend that we should shorten theschool time. The reasons are as follows.Firstly, it will mean enough sleep to students, which in turn will make thestudents more energetic during the day. Besides, whether we will get good marks isnot decided by how much time we spend at school, but how efficient we are. Mostimportantly, with more free time, we can do something interesting and useful as welike.In a word, I support the idea of reducing school time and I'm sure it will bbeneficial to our overall development.

2024届北京专家卷·理科综合(四)4答案部分示例

18.D【命题立意】本题考查匀变速直线运动规律，意在考查学生理解能力、分析综合能力。【解析】设小车经过a、b、c三点时速度分别为v、、,加速度大小为a,由匀变速运动规律可知,=10m/s,=5m/s,x=,=.,由已知得：xk=2.x,联立以上各式解得：=9m/s,故选D。19.AB【命题立意】本题考查功率及功能关系，意在考查学生分析综合能力。【解析】设物体质量为m,已知物体在离地高度为2m时的动能为4J,由动能定理：Fh-mgh=E2-0,再由图像可知,物体上升2m过程中拉力做功为8J,解得:m=0.2 kg,故A正确；拉力做功公式为：W=Fh,根据W-h图像可知，斜率代表拉力F大小，物体上升到离地高度为3m前，拉力F=4N,故B正确；物体从离地3m到5m过程中，由图像知道拉力F=2N,物体重力为2N,故物体速度不变，动能不变，故C错误；物体在离地高度为1m时，由动能定理：Fh-mgh=E-0,解得速度v=2√5m/s,此时拉力功率为P=Fv,解得：P=8√5W,故D错误。故选AB。